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ShaeShae ShaeShae
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Posts: 4
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9 years ago
1) Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.39. What would be the expected homozygous recessive genotype frequency in the next generation? The population is not evolving. Round your answer to two decimal places.

2) Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.37. What would be the expected homozygous dominant genotype frequency in the next generation? The population is not evolving. Round the answer to two decimal places.

3) In a pea plant population, the dominant allele for tallness (T) has a frequency of 0.34. What percent of the population would be expected to be heterozygous (Tt) for the height gene?

4) In a randomly mating population of mice, 12 out of every 100 mice born have white fur, a recessive trait. Calculate the frequency of the allele (G) in the population.

5) In a randomly mating population of mice, 19 out of every  100 mice born have white fur, a recessive trait. Calculate the frequency of the allele (g) in the population.

6) In a randomly mating population of mice, 13 out of every  100 mice born have white fur, a recessive trait. Calculate the homozygous recessive frequency for the population.

7) In a randomly mating population of mice, 5 out of every  100 mice born have white fur, a recessive trait. Calculate the homozygous dominant frequency of the population

8) In a randomly mating population of mice, 21 out of every  100 mice born have white fur, a recessive trait. Calculate the heterozygous frequency for the population

9) A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 140 students, and 23 cannot taste the PTC. Calculate the expected frequencies of the T allele in the student population.

10) A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 130 students, and 13 cannot taste the PTC. Calculate the expected frequencies of the t allele in the student population.

11) A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 125 students, 30 cannot taste the PTC. How many students would you expect to be heterozygous for the tasting gene?  

12) A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of 125 students, 20 cannot taste the PTC. How many students would you expect to be homozygous dominant for the tasting gene?

13) A dominant allele, T, codes for the ability to taste the compound phenylthiocarbamide (PTC). People who are homozygous for the recessive allele, t, are unable to taste PTC. In a genetics class of {y} students, and {x} cannot taste the PTC. You have already calculated the heterozygous and homozygous dominant frequencies. How could you check your answers for for the heterozygous and homozygous dominant frequencies are correct?

14) The M and N factors are glycoproteins that are found on the surface of red blood cells. Unlike other types of red blood cell antigens, the M and N factors do not cause antibody reactions in human blood transfusions. People with type M blood are homozygous for the M allele, and people with type N blood are homozygous for the N allele. Heterozygous individuals have type MN blood. In a study of a population of Inuit living in the Northwest Territories, 512 people had blood type M, 256 had blood type MN, and 32 had blood type N. Calculate the frequency of each allele, M and N, in the population studied. Show all of the steps to your solutions.

15) The M and N factors are glycoproteins that are found on the surface of red blood cells. Unlike other types of red blood cell antigens, the M and N factors do not cause antibody reactions in human blood transfusions. People with type M blood are homozygous for the M allele, and people with type N blood are homozygous for the N allele. Heterozygous individuals have type MN blood. In a study of a population of Inuit living in the Northwest Territories, 640 people had blood type M, 320 had blood type MN, and 40 had blood type N. Calculate the frequency of the genotypes in the population studied. Show all of the steps to your solutions

16) The M and N factors are glycoproteins that are found on the surface of red blood cells. Unlike other types of red blood cell antigens, the M and N factors do not cause antibody reactions in human blood transfusions. People with type M blood are homozygous for the M allele, and people with type N blood are homozygous for the N allele. Heterozygous individuals have type MN blood. In a study of a population of Inuit living in the Northwest Territories,  blood type M had a frequency of 0.66, blood type MN had a frequency of 0.31, and blood type N had a frequency of 0.03.

In a second study group, the frequencies of the genotypes were 0.306 MM, 0.491 MN, and 0.203 NN. Could this second study group have, in fact, come from the previously described Inuit population? Explain your answer

17) A farmer planted some bean seeds. When the seeds germinated, 223 of the seedlings were albino, a recessive trait, and 2570 were green. Determine the proportion of the seedlings that you would expect to be homozygous for the production of chlorophyll. Express your answer as a decimal.

18) A farmer planted some bean seeds. When the seeds germinated, 201 of the seedlings were albino, a recessive trait, and 2600 were green. Determine the number of seedlings that you would expect to be carriers of the albino allele.

19) In populations where it is common for first cousins to marry, some autosomal recessive disorders such as albinism and phenylketonuria are far more likely to occur than elsewhere.

If the frequency of a recessive allele changes from 0.0001 to 0.01 after several generations, the most probable cause is that

20) The two basic types of population genetic questions are illustrated on page 700; questions 2 and 3. Try these without looking at any of your notes, no hints, and imagine this was an exam question.

Question 2: A population has two alleles for a particular gene (B and b), and the allele frequency of B is 0.70. The frequency of the heterozygous genotype is

A) 0.42
   
B) 0.49
   
C) 0.30
   
D) 0.09

21) If 16 people out of 100 in a population have a recessive trait, the frequency of the dominant allele in the population is

A) 0.48

B) 0.40

C) 0.16

D) 0.6

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padrepadre
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9 years ago
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Mastering in Nutritional Biology
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wrote...
8 years ago
Does anyone know the rest of the answers?
Thanks Slight Smile
wrote...
Educator
8 years ago
Does anyone know the rest of the answers?
Thanks Slight Smile

Which #'s exactly
wrote...
8 years ago
I don't understand how to solve question 1 with the fruit flies...
Post Merge: 8 years ago

Does anyone know the rest of the answers?
Thanks Slight Smile

Which #'s exactly


I don't understand how to solve question 1 still..
wrote...
Educator
8 years ago
1) Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.39. What would be the expected homozygous recessive genotype frequency in the next generation? The population is not evolving. Round your answer to two decimal places.

Follow this question Downwards Arrow

Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.30. What would be the expected genotype frequencies for the next generation?

- If the recessive allele has frequency 0.3 then we can say that the dominant allele has frequency 1 - 0.3=0.7

- Now we know the allele frequencies of the parent population (dominant=0.7 and recessive=0.3) we can find out the different genotype frequencies which are: homozygous dominant (LL), heterozygous (Ll) and homozygous recessive (ll)

- Homozygous dominant is when you have both dominant alleles present (LL) = 0.7x0.7=0.49

- Homozygous recessive is when you have both recessive alleles present (Ll) = 0.3x0.3=0.09

- Heterozygous is when you have both one recessive and one dominant, and can be in any order. This one should be calculated by doing 1-(0.49+0.09)=0.42.

Note: We subtract by one since we are dealing with probabilities, and therefore the sum of all probabilities = 1.
wrote...
7 years ago
where does he get 1-0.3=0.7...
and what happens if the frequency is 0.47 instead of 0.39 in this question?
Post Merge: 7 years ago

1) Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.39. What would be the expected homozygous recessive genotype frequency in the next generation? The population is not evolving. Round your answer to two decimal places.

Follow this question Downwards Arrow

Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.30. What would be the expected genotype frequencies for the next generation?

- If the recessive allele has frequency 0.3 then we can say that the dominant allele has frequency 1 - 0.3=0.7

- Now we know the allele frequencies of the parent population (dominant=0.7 and recessive=0.3) we can find out the different genotype frequencies which are: homozygous dominant (LL), heterozygous (Ll) and homozygous recessive (ll)

- Homozygous dominant is when you have both dominant alleles present (LL) = 0.7x0.7=0.49

- Homozygous recessive is when you have both recessive alleles present (Ll) = 0.3x0.3=0.09

- Heterozygous is when you have both one recessive and one dominant, and can be in any order. This one should be calculated by doing 1-(0.49+0.09)=0.42.

Note: We subtract by one since we are dealing with probabilities, and therefore the sum of all probabilities = 1.
wrote...
7 years ago
1) Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.39. What would be the expected homozygous recessive genotype frequency in the next generation? The population is not evolving. Round your answer to two decimal places.

Follow this question Downwards Arrow

Suppose that in a fruit fly population the frequency of the recessive allele that codes for short wings (l) is 0.30. What would be the expected genotype frequencies for the next generation?

- If the recessive allele has frequency 0.3 then we can say that the dominant allele has frequency 1 - 0.3=0.7

- Now we know the allele frequencies of the parent population (dominant=0.7 and recessive=0.3) we can find out the different genotype frequencies which are: homozygous dominant (LL), heterozygous (Ll) and homozygous recessive (ll)

- Homozygous dominant is when you have both dominant alleles present (LL) = 0.7x0.7=0.49

- Homozygous recessive is when you have both recessive alleles present (Ll) = 0.3x0.3=0.09

- Heterozygous is when you have both one recessive and one dominant, and can be in any order. This one should be calculated by doing 1-(0.49+0.09)=0.42.

Note: We subtract by one since we are dealing with probabilities, and therefore the sum of all probabilities = 1.

Do you know the answer for question 13?
wrote...
Staff Member
Educator
7 years ago
Please start a new topic.
Mastering in Nutritional Biology
Tralalalala Slight Smile
wrote...
6 years ago
how about numder 3
wrote...
Educator
6 years ago
https://biology-forums.com/index.php?topic=869969

More answers here!
wrote...
4 years ago
Thank you
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