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Home Q & A Board Science-Related Homework Help Physics
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jen1 jen1
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5 years ago Edited: 5 years ago, jen1
The square plates of a 3000-pF parallel-plate capacitor measure 40 mm by 40 mm and are
separated by a dielectric that is 0.29 mm thick and completely fills the region between the plates. What is the dielectric constant of the dielectric? (Note: Could someone please show me the steps to solving this Problem and not just the answer? Thanks!!)
A) 45       B) 67       C) 50       D) 61       E) 56
Post Merge: 5 years ago

I got it thanks  Slight Smile
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bio_manbio_man
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5 years ago
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Well, we hate to keep threads unanswered:

Area of square plates

A=S2=(40*10-3)2=1.6*10-3 m2

Capacitance

C=KeoA/d

Dielectric constant

=>K=C*d/eoA =(3000*10-12)(0.29*10-3)/(8.85*10-12)(1.6*10-3)

K=61
1

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jen1 Author
wrote...

5 years ago
Thanks for your help!!
patod1
wrote...

Yesterday
Smart ... Thanks!
ealvino1610
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2 hours ago
Correct Slight Smile TY
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