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fodog414 fodog414
wrote...
Posts: 279
9 years ago Edited: 9 years ago, fodog414
So i've been working on these three problems for about an hour to no avail, but for this one I think we need to use Q = m * c * deltaT?
But from there I know i'm not getting the right answer can anyone guide me through it, and please include an explanation 

Thank you for the moment!!

boiling point = 78.40 °C      Hvap(78.40 °C) = 837.0 J/g
melting point = -114.50 °C      Hfus(-114.50 °C) = 109.0 J/g
specific heat gas = 1.430 J/g°C
specific heat liquid = 2.460 J/g°C

A 47.60 g sample of liquid ethanol is initially at -70.70 °C. If the sample is heated at constant pressure (P = 1 atm),   kJ of energy are needed to raise the temperature of the sample to 94.10 °C.
Post Merge: 9 years ago

I think i might have figured it out if anyone could double check.

So, 47.60 x 2.460 x ( 78.40--70.70)= 17459.014

47.60 x 897= 39841.2

47.60 x 1.430 x ( 94.10-78.40)=1068.66

added all of them together to get 58368.8816 J

divided by 1000 to get kj

58.369 <<< is this correct?
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bio_manbio_man
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9 years ago
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fodog414 Author
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9 years ago
Math, chemistry, biology you are my IDOL!!
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Thanks Face with Stuck-out Tongue
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