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MartheGreat MartheGreat
wrote...
Posts: 1
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6 years ago
how do you find the discriminant of a quadratic in standard form? and also find out how many solutions it may have?
Is there any steps or rules to make sure your solutions are reasonable
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wrote...
Educator
6 years ago
Hi there,

Let's say you have

\(2x^3 + 3x + 5\)
-a-         -b-      -c-

... and you want to find the number of roots.

Then use the formula b^2 - 4 (a) (c)

3^2 - 4*2*5
= 9 - 40
= -31

If negative, 0 roots
If 0, 1 root
If greater than 0, 2 roots.

Since we get -31, we have 0 roots here. AND, the graph proves it as the curve doesn't cross the x-axis.



Hope this helps, ask more questions if you need help.


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