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OldSpice OldSpice
wrote...
Posts: 6432
9 years ago
If 45.5 mL of 0.150 M sodium sulfate solution reacts completely with aqueous barium nitrate, what is the mass of BaSO4 (233.40 g/mol) precipitate?
   Ba(NO3)2(aq) + Na2SO4(aq) ? BaSO4(s) + 2 NaNO3(aq)
A) 0.0292 g
B) 0.769 g
C) 1.59 g
D) 6.83 g
E) 34.1 g
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Answer accepted by topic starter
ElectricElectric
wrote...
Top Poster
Posts: 6431
9 years ago Edited: A year ago, bio_man
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.silent.boss

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OldSpice Author
wrote...
9 years ago
Perfect!

..Thank you so much for your support
wrote...
9 years ago
My pleasure
.silent.boss
wrote...
3 years ago
Awesomes
wrote...
3 years ago
thank you
wrote...
3 years ago
Thank you
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