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OldSpice OldSpice
wrote...
Posts: 6432
9 years ago
If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH, what volume of potassium hydroxide is required?
   KHC8H4O4(aq) + KOH(aq) ? K2C8H4O4(aq) + 2 H2O(l)
A) 12.5 mL
B) 20.0 mL
C) 25.0 mL
D) 40.0 mL
E) 50.0 mL
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Answer accepted by topic starter
ElectricElectric
wrote...
Top Poster
Posts: 6431
9 years ago
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.silent.boss
OldSpice Author
wrote...
9 years ago
Perfect!

..Thank you so much for your support
wrote...
9 years ago
My pleasure
.silent.boss
Anonymous
wrote...
10 months ago
Help! The answer is missing an explanation...
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