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Home Q & A Board Science-Related Homework Help High School Level Science
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astuckey astuckey
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5 years ago
A 100 MW power station generates energy at 26.0 kV.  The power lines must carry only 200 A of current to be efficient enough.  To what voltage must the potential be increased?
Show your work (formula, substitution, answer rounded correctly and with the appropriate unit).
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#1
Educator
5 years ago
power = voltage \(\times \) current

\(P=VI\)

We are told the power (100MW = 100x10⁶ W)

We are told the current we want (I = 200A)

So we can find the voltage we want

Rearrange the formula to get V isolated

V = P/I

Put the value in

V = 100x10⁶ / 200

V = 5 x10⁵ V

If you want the answer in kV, divide by 1000

V = 500kV

(The value of 26.0kV is not needed here.)
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