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How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas?

Asfian

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How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas?

How many grams of CaCl2 are formed when 30.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas?

2 Ca(OH)2(aq) + 2 Cl2(g) Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l)

A) 0.00395 g
B) 0.00789 g
C) 0.0158 g
D) 0.0253 g

Textbook

Chemistry: A Molecular Approach

Chemistry: A Molecular Approach

Edition: 4^th

Author: Tro

Read 876 times

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spsjr15

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5 years ago Edited: 2 years ago, bio_man

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maddiecothran

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4 years ago

thanks

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thank you

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landon r.

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thanks

Katie B.

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ok

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thank you this was helpful

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