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einsteindude einsteindude
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6 years ago
If 26.5 mL of 0.222 M HCl reacts with excess Mg, how many mL of hydrogen gas are produced at STP?

Mg(s) + 2HCl(aq) Rightwards Arrow MgCl2(aq) + H2(g)

A) 132 mL
B) 65.9 mL
C) 26.5 mL
D) 22 400 mL
E) 165 mL
Textbook 

Conceptual Physical Science


Edition: 6th
Authors:
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f_zah1f_zah1
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6 years ago Edited: 2 days ago, bio_man
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B

n HCl = ( 0.222 mol/L )( 26.5 mL ) ( 1.0 L / 1000 mL ) = 0.005883 moles HCl

n H2 produced = ( 0.005883 mol HCl reacted ) ( 1 mol H2 produce/ 2 mol HCl reacted )

n H2 produced = 0.0029415 mole H2 produced

Vstp H2 = ( 0.0029415 mol H2 ) ( 22.42 L / mol H2 at STP ) ( 1000 mL / 1 L )

Vstp H2 = 65.9 mL at STP H2 produced

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