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Catracho Catracho
wrote...
Posts: 529
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5 years ago Edited: 5 years ago, bio_man
For the experiment described​ below, let x determine a random​ variable, and use knowledge of probability to prepare a probability distribution.

Two names are drawn from a hat, signifying who should go pick up pizza Six of the names are on the swim team and four are not The number of swimmers selected is counted.

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wrote...
Educator
5 years ago
Here are my calculations (please note I'm not certain, need to think further about it; will update the topic)

The probability of 0 swimmers is

First selection: (4/10)
Second selection: (3/9)

(4/10) * (3/9) = 2 / 15 chance that x = 0 swimmers are selected.

---

The probability of 1 swimmer is

First selection: (6/10)
Second selection: (4/9)

(6/10) * (4/9) = 4 / 15 that x = 1 swimmers are selected.

---

The probability of 2 swimmer is

First selection: (6/10)
Second selection: (5/9)

(6/10) * (5/9) = 1 / 3 chance that x = 2 swimmers are selected.
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