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smolie04 smolie04
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2 years ago

Figure 5.21




In Figure 5.21, a block of mass 7.0 kg on a tabletop is attached by strings to vertically hanging masses, 12 kg and 10 kg, as shown.  The strings and pulleys are massless, the pulleys are frictionless, but the coefficient of kinetic friction between the block and the tabletop is 0.10. Describe the motion of the block, including the magnitude and direction of the acceleration.  
Textbook 

College Physics


Edition: 10th
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Ceren C.Ceren Celik
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2 years ago
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acceleration = 0.44 m/s2; the block accelerates to the left.
Since block A is heavier system moves along left side.i.e C moves upwards and A downwards
acceleration=(net pulling force)/mass of the system
acceleration=(12-10-7*0.1)g/(12+10+7)
acceleration=0.439m/s^2
Both A and C are pulled by gravity but both can not move downwards because strings length remains constant.Now A being heavier Will try to move downwards and its motion will be opposed by 2 forces weight of block C and Frictional force acting On B.Considering above as a system the net downward force acting on the system is Weight of A -Weight of C -Frictional force acting on c.
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