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Catracho Catracho
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Posts: 529
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5 years ago
In a sample of 800 U.S.​ adults, 195 dine out at a resaurant more than once per week.
Two
Two U.S. adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S.​ adults, complete parts​ (a) through​ (d).
​(a) Find the probability that both adults dine out more than once per week.
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Educator
5 years ago Edited: 5 years ago, bio_man
a) (195/800)*(195/800) = 0.059 (round to 3 decimal places) -- mind you, this is NOT a percent

What's confusing to me is the "without replacement" part, which means once one is chosen, the second factor reflects the change, i.e. 195 -> 194 and 800 becomes 799. If that's the case, you may have to do the following:

(195/800)*(194/799) = 0.059 instead (probably a good idea to watch the video below for a better explanation).

Luckily, since it's only to 3 decimal places, doing it one way over the other will not make a difference!

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