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Express Lane Plus
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5 months ago
 The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be ... The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be approximated by a normal​ distribution, as shown in the graph to the right. Answer parts​ (a) and​ (b) below. Attached file Thumbnail(s): You must login or register to gain access to this attachment. Read 116 times 4 Replies
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Staff Member
5 months ago
 a) 1.645 = (X - 6.1)/1X = 1.645 + 6.1X = 7.745 or 7.75 on rounding to 2 dpsShortest sleeping time that place a resident in the top 5% of is 7.75 hoursb)Between what two values does the middle 50% of the sleep times lie? The z values concerned are - 0.675 and + 0.675- 0.675 = (X - 6.1)/1X = 6.1 - 0.675X = 5.425 or 5.43+ 0.675 = (X - 6.1)/1X = 6.1 + 0.675X = 6.775 or 6.78Middle 50% sleep times lie between 5.43 hours and 6.78 hours
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Express Lane Plus
5 months ago
 Quote from: bolbol (5 months ago) a) 1.645 = (X - 6.1)/1 X = 1.645 + 6.1 X = 7.745 or 7.75 on rounding to 2 dps Shortest sleeping time that place a resident in the top 5% of is 7.75 hours b)Between what two values does the middle 50% of the sleep times lie? The z values concerned are - 0.675 and + 0.675 - 0.675 = (X - 6.1)/1 X = 6.1 - 0.675 X = 5.425 or 5.43+ 0.675 = (X - 6.1)/1 X = 6.1 + 0.675 X = 6.775 or 6.78 Middle 50% sleep times lie between 5.43 hours and 6.78 hours it was incorrect !!!!!!
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Educator
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Posts: 24524
5 months ago Edited: 5 months ago, bio_man
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Educator
5 months ago
 Quote from: bolbol (5 months ago)b)Between what two values does the middle 50% of the sleep times lie?Where did you find this question?
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