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Home Q & A Board Science-Related Homework Help Mathematics Statistics and Probability
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Catracho Catracho
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5 years ago
The average time spent sleeping​ (in hours) for a group of medical residents at a hospital can be approximated by a normal​ distribution, as shown in the graph to the right. Answer parts​ (a) and​ (b) below.
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#1
Staff Member
5 years ago
a)
1.645 = (X - 6.1)/1
X = 1.645 + 6.1
X = 7.745 or 7.75 on rounding to 2 dps
Shortest sleeping time that place a resident in the top 5% of is 7.75 hours

b)Between what two values does the middle 50% of the sleep times lie?


The z values concerned are - 0.675 and + 0.675
- 0.675 = (X - 6.1)/1
X = 6.1 - 0.675
X = 5.425

or 5.43+ 0.675 = (X - 6.1)/1
X = 6.1 + 0.675
X = 6.775 or 6.78
Middle 50% sleep times lie between 5.43 hours and 6.78 hours
Catracho Author
wrote...
#2
5 years ago
Quote from: bolbol (5 years ago)
a) 1.645 = (X - 6.1)/1 X = 1.645 + 6.1 X = 7.745 or 7.75 on rounding to 2 dps Shortest sleeping time that place a resident in the top 5% of is 7.75 hours b)Between what two values does the middle 50% of the sleep times lie? The z values concerned are - 0.675 and + 0.675 - 0.675 = (X - 6.1)/1 X = 6.1 - 0.675 X = 5.425 or 5.43+ 0.675 = (X - 6.1)/1 X = 6.1 + 0.675 X = 6.775 or 6.78 Middle 50% sleep times lie between 5.43 hours and 6.78 hours
it was incorrect !!!!!!
Answer accepted by topic starter
bio_manbio_man
wrote...
#3
Educator
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Posts: 33241
Rep: 3442 15
5 years ago Edited: 5 years ago, bio_man
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#4
Educator
5 years ago
Quote from: bolbol (5 years ago)
b)Between what two values does the middle 50% of the sleep times lie?

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