Top Posters
Since Sunday
5
o
5
4
m
4
b
4
x
4
a
4
l
4
t
4
S
4
m
3
s
3
New Topic  
Annlore1345 Annlore1345
wrote...
Posts: 15
Rep: 0 0
4 years ago
An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What mass ( g ) of KOH was in the original sample?

A)0.129
B)0.190
C)0.173
D)0.207
E)0.215
Read 573 times
10 Replies
Replies
Answer verified by a subject expert
bio_manbio_man
wrote...
Educator
Top Poster
Posts: 33224
4 years ago Edited: 4 years ago, bio_man
Sign in or Sign up in seconds to unlock everything for free

Related Topics

wrote...
Educator
4 years ago
Topic updated Upwards Arrow
Annlore1345 Author
wrote...
4 years ago
Thank you so much, but from where do u get the 56.1 g.
wrote...
Educator
4 years ago
That's the molar mass of NaOH
Annlore1345 Author
wrote...
4 years ago
Ohh ok ok, thanks again
wrote...
Educator
4 years ago
Ohh ok ok, thanks again

You're welcome. Let us know if you have any other questions (chem, math, etc)
Annlore1345 Author
wrote...
4 years ago
Hello I was calculating the molar mass and that not the answer that I got. I get 39.99g
wrote...
Educator
4 years ago
Sorry, I meant molar mass of KOH 🤦‍♂️
Annlore1345 Author
wrote...
4 years ago
Ohh ok it's fine thank you so muchh☺️
wrote...
4 years ago
thank you
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1113 People Browsing
Related Images
  
 284
  
 1122
  
 187
Your Opinion