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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Annlore1345 Annlore1345
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4 years ago
An aliquot( 28.7 mL ) of a KOH solution required 31.3 mL of 0.118 M HCI for neutralization. What mass ( g ) of KOH was in the original sample?

A)0.129
B)0.190
C)0.173
D)0.207
E)0.215
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bio_manbio_man
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#1
Educator
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Posts: 33233
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4 years ago Edited: 4 years ago, bio_man
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wrote...
#2
Educator
4 years ago
Topic updated Upwards Arrow
Annlore1345 Author
wrote...
#3
4 years ago
Thank you so much, but from where do u get the 56.1 g.
wrote...
#4
Educator
4 years ago
That's the molar mass of NaOH
Annlore1345 Author
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#5
4 years ago
Ohh ok ok, thanks again
wrote...
#6
Educator
4 years ago
Quote from: Annlore1345 (4 years ago)
Ohh ok ok, thanks again

You're welcome. Let us know if you have any other questions (chem, math, etc)
Annlore1345 Author
wrote...
#7
4 years ago
Hello I was calculating the molar mass and that not the answer that I got. I get 39.99g
wrote...
#8
Educator
4 years ago
Sorry, I meant molar mass of KOH 🤦‍♂️
Annlore1345 Author
wrote...
#9
4 years ago
Ohh ok it's fine thank you so muchh☺️
wrote...
#10
4 years ago
thank you
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