× Didn't find what you were looking for? Ask a question

Top Posters
Since Sunday
9
9
8
8
8
8
7
7
7
7
7
7

# What is the volume rate of flow?

wrote...
Posts: 36
Rep: 0 0
A month ago
 What is the volume rate of flow? A 6.8 cm diameter horizontal pipe gradually narrows to 5.2 cm . When water flows through this pipe at a certain rate, the gauge pressure in these two sections is 33.0 kPa and 22.0 kPa , respectively. Read 54 times 1 Reply
Related Topics
Replies
wrote...
Educator
A month ago
 We're looking for m^3 / s (volume flow rate per every 1 second).Use the equation of continuity to relate the volume flow of water at the two locations, and use Bernoulli’s equation to relate the pressure conditions at the two locations. We assume that the two locations are at the same height. Express the pressures as atmospheric pressure plus gauge pressure. We use subscript "1" for the larger diameter, and subscript "2" for the smaller diameter.$$A_1v_1=\pi r_1^2\times \sqrt{\frac{2\left(P_1-P_2\right)}{\rho \left(\frac{r_1^4}{r_2^4}-1\right)}}$$Now substitute, make sure you divide each diameter by 2 to get the radius, and convert them to meters:6.8 / 2 / 100 = 0.034 m5.2 / 2 / 100 = 0.026 m33.0 kPa > 33 000 Pa22.0 kPa > 22 000 Pa$$A_1v_1=\pi \left(0.034\right)^2\times \sqrt{\frac{2\left(33000-22000\right)}{1000\left(\frac{0.034^4}{0.026^4}-1\right)}}$$Calculate:$$A_1v_1=\pi \left(0.034\right)^2\times \sqrt{\frac{2\left(33000-22000\right)}{1000\left(\frac{0.034^4}{0.026^4}-1\right)}}=1.2\cdot 10^{-2}\ \frac{m^3}{\sec }$$
 The best way to say thank you is with a positive review:   https://trustpilot.com/review/biology-forums.com  Your support goes a long way!▶ Make a note request here
Explore