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3 weeks ago
The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant times the density of the liquid, P=ghd. How high a column of methanol (d= 0.79 g/mL) would be supported by a pressure that supports a 713 mm column of mercury (d = 13.6 g/mL)?

A) 713 mm

B) 41 mm

C) 1.2 x 104 mm

D) 9.7x 103 mm

 E) 17 mm
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3 weeks ago
Answer:

C) 1.2 x 104 mm


Explanation:

The pressure exerted by a column of liquid is equal to the product of the height of the column times the gravitational constant times the density of the liquid i.e.

P = d g h

Pressure, P = 713 mm column of mercury

Density, d = 0.79 g/ml = 790 kg/m³

We have to find how high a column of methanol would be supported by a pressure P. Let the height is h. So,



g = acceleration due to gravity 9.8 m/s²

We know that, 1 mm of mercury = 133.32 Pa

 713 mm of mercury = 95058.9 Pa



h = 12.27 m

Hence, this is the required solution.

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wrote...
3 weeks ago
Thank you so much☺️
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