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Catracho Catracho
wrote...
Posts: 529
Rep: 2 0
4 years ago
Auto pistons at Wemming​ Chung's plant in Shanghai are produced in a forging​ process, and the diameter is a critical factor that must be controlled. From sample sizes of
10
10 pistons produced each​ day, the mean and the range of this diameter have been as​ follows
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wrote...
Educator
4 years ago
155.16

Just add the numbers in the second column and divide by 5. Technically they want the mean of the means
Catracho Author
wrote...
4 years ago
155.16 Just add the numbers in the second column and divide by 5. Technically they want the mean of the means
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bio_manbio_man
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Educator
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4 years ago
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Catracho Author
wrote...
4 years ago
Hi, this question has several parts and it gives me the next part, just after i answer the previous part
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Educator
4 years ago
So now they're looking for the UCL, we have everything we need:

UCL = (average of the averages) + (0.577)(average of the ranges)
UCL = 155.16 + 0.577(4.44) = 157.72

***0.577 is obtained from this chart https://youtu.be/p9NOaydinmQ?t=241

Hope that helps!
wrote...
Educator
4 years ago
UCL = 155.16 + 0.308(4.44) = 156.52 This is your answer, ignore the previous

**0.308 Sample Size of 10 uses this number!
Catracho Author
wrote...
4 years ago
UCL = 155.16 + 0.308(4.44) = 156.52 This is your answer, ignore the previous **0.308 Sample Size of 10 uses this number!
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wrote...
Educator
4 years ago
156.52 is your answer for this question, substitute that number into that last input box
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