The health care provider prescribes 325 mg of ferrous sulfate to a patient who is diagnosed with anemia. The drug is to be administered by orogastric tube. The drug concentration is 60 mg/mL. The drug osmolality is 4700 mOsm. The desired osmolality is 500 mOsm. How much water dilution should the nurse prepare to obtain the desired osmolality? Record your answer using one decimal place. __________mL
Ok, so just revisiting this, I think my first attempt it wrong.
We're told it's 60 mg of solute (drug) per 1 mL of solution. To get its volume, take 1 ml/60 mg * 325 mg, we get the volume as: 5.416 mL (this will serve as V
1)
Also, initially it's 4700 mOsm, which is the same as 4.7 Osm, which is the same as 4.7 osmoles per 1 liter.
The dissociation equation for this molecule is: FeSO4 > Fe
2+ + SO4
2-, so ... 2 solute particles per 1 mole of FeSO4, AKA 2 osmoles / 1 mole of FeSO4
If we multiple 4.7 osmoles/1L by 1 mole of FeSO4 / 2 osmoles, we get C
1 = 2.35 moles /1 Liter
Let's do the same for C
2: 0.500 osmoles / 1 L * 1 mole of FeSO4 / 2 osmoles = 0.250 moles /1 Liter
Let's use the formula V
1C
1 = V
2C
2(5.416)*(2.35) = (x)*(0.250)
x = 50.9 mL >>> You can try this as your answer too
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