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Male players at the high school, college and professional ranks use a regulation basketball that ...
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Male players at the high school, college and professional ranks use a regulation basketball that ...
Male players at the high school, college and professional ranks use a regulation basketball that weighs 22.0 ounces with a standard deviation of 1.0 ounce. Assume that the weights of basketballs are approximately normally distributed.
Roughly what percentage of regulation basketballs weigh less than 20.7 ounces? Round to the nearest tenth of a percent.
▸ 40.3% of the basketballs will weigh less than 20.7 ounces.
▸ 5.7% of the basketballs will weigh less than 20.7 ounces.
▸ 22.3% of the basketballs will weigh less than 20.7 ounces.
▸ 9.7% of the basketballs will weigh less than 20.7 ounces.
Textbook
Introductory Statistics: Exploring the World Through Data
Edition:
2
^{nd}
Authors:
Gould, Ryan
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9.7% of the basketballs will weigh less than 20.7 ounces.
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annabananerz
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#2
A week ago
Use the following information for the question. Male players at the high school, college and professional ranks use a regulation basketball that weighs 22.0 ounces with a standard deviation of 1.0 ounce. Assume that the weights of basketballs are approximately normally distributed.
Roughly what percentage of regulation basketballs weigh less than 20.7 ounces? Round to the nearest tenth of a percent.
Answered- 9.7% of the basketballs will weigh less than 20.7 ounces
If a regulation basketball is randomly selected, what is the probability that it will weigh between 20.5 and 23.5 ounces? Round to the nearest thousandth.
____??___
A) 0.134 B) 0.267 C) 0.866 D) 0.704
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sudenzia
wrote...
#3
A week ago
(A)
mean = 22
Std Dev (s) =1
To find : P( x < 20.7 )
z = ( x - u )/s = ( 20.7 - 22 )/1 = -1.3
P( x < 20.7) = P( Z < -1.3)
= 0.0968 _ _ _ _ _ _ _ _ _ (From Z-table)
= 9.68%
(B)
mean = 22
std dev = 1
Find : P( 20.5 < X < 23.5 )
We convert to standard normal form, by z = (x - u )/s
so z1 = (20.5 - 22 )/1 = -1.5
& z2 = (23.5 - 22 )/1 = 1.5
P( 20.5 < X < 23.5) = P(z1 < Z < z2) = P( Z < 1.5) - P(Z < -1.5)
= 0.93319 - 0.06681
= 0.86638 _ _ _ _ _ _ _ _ _ (From Z-table)
ANSWER: C) 0.866
Quote from: annabananerz (A week ago)
Use the following information for the question. Male players at the high school, college and professional ranks use a regulation basketball that weighs 22.0 ounces with a standard deviation of 1.0 ounce. Assume that the weights of basketballs are approximately normally distributed.
Roughly what percentage of regulation basketballs weigh less than 20.7 ounces? Round to the nearest tenth of a percent.
Answered- 9.7% of the basketballs will weigh less than 20.7 ounces
If a regulation basketball is randomly selected, what is the probability that it will weigh between 20.5 and 23.5 ounces? Round to the nearest thousandth.
____??___
A) 0.134 B) 0.267 C) 0.866 D) 0.704
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