Top Posters
Since Sunday
V
9
C
7
B
7
7
a
7
S
7
l
7
l
7
j
7
B
7
k
7
s
6
New Topic  
asdoooeoe asdoooeoe
wrote...
Posts: 472
2 years ago
Male players at the high school, college and professional ranks use a regulation basketball that weighs 22.0 ounces with a standard deviation of 1.0 ounce. Assume that the weights of basketballs are approximately normally distributed.

Roughly what percentage of regulation basketballs weigh less than 20.7 ounces? Round to the nearest tenth of a percent.

▸ 40.3% of the basketballs will weigh less than 20.7 ounces.

▸ 5.7% of the basketballs will weigh less than 20.7 ounces.

▸ 22.3% of the basketballs will weigh less than 20.7 ounces.

▸ 9.7% of the basketballs will weigh less than 20.7 ounces.
Textbook 

Introductory Statistics: Exploring the World Through Data


Edition: 2nd
Authors:
Read 90 times
3 Replies
Replies
Answer verified by a subject expert
KaajalpKaajalp
wrote...
Posts: 367
2 years ago
Sign in or Sign up in seconds to unlock everything for free
More questions for this book are available here
9.7% of the basketballs will weigh less than 20.7 ounces.
1

Related Topics

wrote...
A week ago
Use the following information for the question. Male players at the high school, college and professional ranks use a regulation basketball that weighs 22.0 ounces with a standard deviation of 1.0 ounce. Assume that the weights of basketballs are approximately normally distributed.

Roughly what percentage of regulation basketballs weigh less than 20.7 ounces? Round to the nearest tenth of a percent.

Answered- 9.7% of the basketballs will weigh less than 20.7 ounces

If a regulation basketball is randomly selected, what is the probability that it will weigh between 20.5 and 23.5 ounces? Round to the nearest thousandth.

____??___

A) 0.134 B) 0.267 C) 0.866 D) 0.704
wrote...
A week ago
(A)

mean = 22
Std Dev (s) =1
To find : P( x < 20.7 )
z = ( x - u )/s = ( 20.7 - 22 )/1 = -1.3

P( x < 20.7) = P( Z < -1.3)
= 0.0968 _ _ _ _ _ _ _ _ _ (From Z-table)
= 9.68%
(B)

mean = 22
std dev = 1
Find : P( 20.5 < X < 23.5 )
We convert to standard normal form, by z = (x - u )/s
so z1 = (20.5 - 22 )/1 = -1.5
& z2 = (23.5 - 22 )/1 = 1.5

P( 20.5 < X < 23.5) = P(z1 < Z < z2) = P( Z < 1.5) - P(Z < -1.5)
= 0.93319 - 0.06681
= 0.86638 _ _ _ _ _ _ _ _ _ (From Z-table)
ANSWER: C) 0.866

Use the following information for the question. Male players at the high school, college and professional ranks use a regulation basketball that weighs 22.0 ounces with a standard deviation of 1.0 ounce. Assume that the weights of basketballs are approximately normally distributed.

Roughly what percentage of regulation basketballs weigh less than 20.7 ounces? Round to the nearest tenth of a percent.

Answered- 9.7% of the basketballs will weigh less than 20.7 ounces

If a regulation basketball is randomly selected, what is the probability that it will weigh between 20.5 and 23.5 ounces? Round to the nearest thousandth.

____??___

A) 0.134 B) 0.267 C) 0.866 D) 0.704
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  49 People Browsing
 125 Signed Up Today
Related Images
 208
 75
 424
Your Opinion
Do you believe in global warming?
Votes: 328

Previous poll results: Who's your favorite biologist?