Physics 2 help question

Given:
•   Diameter of the circular wire loop=6.9 cm=0.069 m
•   Radius of the circular wire loop  r=0.069/2=0.0345 m radius

Use
Φ=BACosθ... and plug in the points

where Φ is the Magnetic Flux

A is the area and theta θ is the angle between the magnetic field and the vector normal (perpendicular) to the area.

B=magnetic field strength -(T-tesla)

In case of cosine formula, the angle is defined between B and normal to the surface A.

Whereas in case of sine formula, the angle is defined between B and the surface A

The unit of magnetic flux is the weber. 1 Wb= 1 T m2.

That's why we had to convert the diameter from cm to m

The Areas of a Circle, A = π r²

A= π x (0.0345 m)^2 = 0.00373928065 m2

Φ=0.00373928065 m2x 0.68Tx cos0° =0.00254271084 Wb

Φ=0.00373928065 x -0.29Tx cos0° =- 0.00108439138 Wb

Farad Law ε=-N(ΔΦ/Δt)

convert ms to s, 1 s = 1000ms thus Δt = 0.17 s
ε = (0.00254271084 Wb + 0.00108439138 Wb) / (0.17 s)
ε = 0.02133589541 V
ε  = 0.02 V (two significant figures)

Make sure always not to round up or down till the final answer