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ohemati ohemati
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Posts: 50
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3 years ago

Samuel has two 4-sided dice. The sides of each die have the numbers 1, 2, 3 and 4. Because the dice and pyramid shaped, when Samuel rolls the dice, each lands with three faces showing and one face down.
If Samuel rolls his dice, the probability that the numbers face down have a difference of 2 is
a. 1/9
b. 1/8
c. 1/4
d. 1/3


If  P(B) = 4/5 and P(B And A) = 3/5 , where A and B are dependent events, then P(A|B) equals
a. 7/5   b.3/4 c. 1/5  d.12/25


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wrote...
Educator
3 years ago
Samuel has two 4-sided dice. The sides of each die have the numbers 1, 2, 3 and 4. Because the dice and pyramid shaped, when Samuel rolls the dice, each lands with three faces showing and one face down. If Samuel rolls his dice, the probability that the numbers face down have a difference of 2 is a. 1/9 b. 1/8 c. 1/4 d. 1/3

Since order doesn't matter, we have 1/16 chance of select either 4,2 and 3,1 -- both make a difference of 2.

1/16 + 1/16 = 2/16 = 1/8

wrote...
Educator
3 years ago
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