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cmesser94 cmesser94
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2 years ago
A line in the spectrum of atomic mercury has a wavelength of 258 nm. When mercury emits a photon of light at this wavelength, the frequency of this light is:


8.61 × 10–16 s–1



7.70 × 10–19 s–1



1.16 × 1015 s–1



77.3 s–1



none of these are correct
Textbook 
Chemistry: An Atoms First Approach

Chemistry: An Atoms First Approach


Edition: 3rd
Authors:
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itsrhubarbitsrhubarb
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2 years ago
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More solutions for this book are available here
1.16 × 1015 s–1

1

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Anonymous
wrote...
9 months ago
The wavelength and frequency of all types of waves (not just electromagnetic waves) are related according to the equation:

wavespeed = wavelength * frequency

For a photon, the wave speed is the speed of light = 2.998*10^8 m/s, so

wavelength = (2.998*10^8 m/s)/(254*10^-9 m)
wavelength = 1.18*10^15 Hz
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