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What quantity of charge is required to reduce 32.9 g of CrCl3 to chromium metal? (1 faraday = 96,485 coulombs)
pjmierek92
pjmierek92
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What quantity of charge is required to reduce 32.9 g of CrCl3 to chromium metal? (1 faraday = 96,485 coulombs)
What quantity of charge is required to reduce 32.9 g of CrCl
3
to chromium metal? (1 faraday = 96,485 coulombs)
▸
2.00 × 10
4
C
▸
6.01 × 10
4
C
▸
9.52 × 10
2
C
▸
3.17 × 10
2
C
▸
None of these are correct.
Textbook
Chemistry: An Atoms First Approach
Edition:
3
rd
Authors:
Zumdahl, DeCoste
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liuzy
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6.01 × 10
4
C
1
1 Vote
Joshua Arnold Arriesgado
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Joshua A.
wrote...
#2
A year ago
thank youu!!
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gmiannotti
wrote...
#3
A year ago
What quantity of charge is required to reduce
27.2 g
of CrCl3 to chromium metal? (1 faraday = 96,485 coulombs)
Report
habiba
wrote...
#4
Staff Member
A year ago
Quote from: gmiannotti (A year ago)
What quantity of charge is required to reduce
27.2 g
of CrCl3 to chromium metal? (1 faraday = 96,485 coulombs)
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