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arlinguillen arlinguillen
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A year ago
How many grams of CaCl2 are formed when 15.00 mL of 0.00237 mol L-1 Ca(OH)2(aq) reacts with excess Cl2 gas?

2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l)


▸ 0.00197 g

▸ 0.00394 g

▸ 0.00789 g

▸ 0.0507 g
Textbook 

General Chemistry: Principles and Modern Applications


Edition: 11th
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calebmachariacalebmacharia
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A year ago
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0.00197 g
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