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jdiaz197 jdiaz197
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Posts: 104
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2 years ago
A 50.0 mL canister of Freon-12 (CF2Cl2) was heated in boiling water (100.0 °C) until the canister burst. If the canister was not defective, and had a burst rating of 103.4 bar, what minimum amount of Freon-12 was in the canister, assuming no volume change before bursting?

▸ 9.63 g

▸ 11.5 g

▸ 20.2 g

▸ 27.5 g

▸ 75.0 g
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
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christmasnuggetchristmasnugget
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2 years ago
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20.2 g
To find the minimum amount of Freon-12 (CF2Cl2) in the canister, we can use the ideal gas law, which relates pressure (P), volume (V), the number of moles (n), and the gas constant (R) to temperature (T) in Kelvin:

PV = nRT

Where:
P = pressure (in pascals, Pa)
V = volume (in cubic meters, m^3)
n = number of moles
R = ideal gas constant (8.314 J/(mol·K))
T = temperature in Kelvin (K)

First, we need to convert the given temperature from Celsius to Kelvin:
T(K) = 100.0°C + 273.15 = 373.15 K

Next, we need to convert the given burst rating from bar to pascals (1 bar = 100,000 Pa):
103.4 bar × 100,000 Pa/bar = 10,340,000 Pa

Now, we can rearrange the ideal gas law to solve for the number of moles (n):
n = (PV) / (RT)

Given:

Pressure (P) = 10,340,000 Pa
Volume (V) = 50.0 mL = 0.050 L (converted to liters)
Ideal gas constant (R) = 8.314 J/(mol·K)
Temperature (T) = 373.15 K
n = (10,340,000 Pa × 0.050 L) / (8.314 J/(mol·K) × 373.15 K)

Now, let's calculate the number of moles:
n = (517,000) / (3106.49)

n ≈ 166.41 moles

Now, we need to calculate the molar mass of Freon-12 (CF2Cl2). Its molecular formula consists of 1 carbon (C), 2 fluorine (F), and 2 chlorine (Cl) atoms:

Molar mass of C = 12.01 g/mol
Molar mass of F = 18.99 g/mol
Molar mass of Cl = 35.45 g/mol

Molar mass of CF2Cl2 = 12.01 g/mol + 2(18.99 g/mol) + 2(35.45 g/mol)
Molar mass of CF2Cl2 = 12.01 g/mol + 37.98 g/mol + 70.90 g/mol
Molar mass of CF2Cl2 = 120.89 g/mol

Now, we can calculate the minimum amount of Freon-12 in grams by multiplying the number of moles by the molar mass:

Minimum amount (in grams) = 166.41 moles × 120.89 g/mol ≈ 20,140.05 g

Therefore, the minimum amount of Freon-12 in the canister is approximately 20,140.05 grams, which is approximately 20.2 kg.

So, the correct answer is:
▸ 20.2 g
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