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# Determine the enthalpy change in the following equation: Cl2(g) + H2O(l) 2 HCl(g) + 1/2 O2(g) fH ...

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A year ago
Determine the enthalpy change in the following equation:

Cl2(g) + H2O(l) → 2 HCl(g) + 1/2 O2(g)
Δf H2O(l) = -285.8 kJ/mol
Δf HCl(g) = -92.31 kJ/mol

▸ 193.5 kJ/mol

▸ -470.4 kJ/mol

▸ 470.4 kJ/mol

▸ 101.2 kJ/mol

▸ -101.2 kJ/mol
Textbook

## General Chemistry: Principles and Modern Applications

Edition: 11th
Authors:
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ethom947ethom947
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 Determine the enthalpy change in the following equation:2/3 H2S(g) + O2(g) → 2/3 SO2(g) + 2/3 H2O(l)Given:ΔH°f H2O(l) = -285.8 kJ/molΔH°f H2S(g) = -20.63 kJ/molΔH°f SO2(g) = -296.8 kJ/mol
wrote...
A month ago
 Quote from: Jslemin (A month ago) Determine the enthalpy change in the following equation: 2/3 H2S(g) + O2(g) → 2/3 SO2(g) + 2/3 H2O(l) Given: ΔH°f H2O(l) = -285.8 kJ/mol ΔH°f H2S(g) = -20.63 kJ/mol ΔH°f SO2(g) = -296.8 kJ/mol Attached file Thumbnail(s): You must login or register to gain access to this attachment.