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maryberryhermee maryberryhermee
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A year ago
A solution of Al(NO3)3(aq) is electrolyzed by passing 144 A of current for 102 min. What mass of aluminum plates out?

▸ 27.4 g

▸ 760 g

▸ 82.1 g

▸ 2.3 g

▸ 75.3 g
Textbook 

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
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nahomf12nahomf12
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A year ago
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More questions for this book are available here
82.1 g

Answer:

Given current=144 A =144 C/s,

time t=102 minutes =102 x 60 s=6120 s.

Faraday constant=96500 C/mol x e^-

Here Al^+3(aq) +3e^- ------> Al(s)

From Faraday's law,

Moles of Al x 3 e^- x 96500 C/mol. e^- = 144 C/s x 6120 s

Therefore moles of Al=(144 x 6120)/(3x96500)=3.044 mol.

Molar mass of Al=26.98 g/mol

Therefore mass of Al=moles x molar mass

Mass of Al=3.044 mol x 26.98 g/mol=82.131 g.
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