How to get the derivative of x/(2-sqrt(x)) using delta method

hello, i am yareti, plz wait 5 minutes

Post Merge: 2 years ago

Post Merge: 2 years ago

f(x)= x/2-sqrt(X) delta metodo.
dy/dx=lim delta x =delta y/delta x
o  f(x)=lim delta x = f(x+deltax)-(f(x))/delta x

f(x+delta x)=    [x/2(sqrt(x))+delta x ]   
f(x)=                   [x/2-sqrt(X) ]
por lo tanto
  [x/2(sqrt(x))+delta x ]    -   [x/2-sqrt(X) ]/delta x

teorema,  a3 - b3  /a2+a*b+b2 = a-b

por lo tanto,

[x/2(sqrt(x))+delta x ]3    -    [x/2-sqrt(X) ]3
/////////////////////////////////////between dividing//////////////////////////////////////////////////
( [x+ delta x /2-sqrt(X) ])2+ [x+ delta x /2-sqrt(X) ]* [x/2-sqrt(X) ] +  [x/2-sqrt(X) ]2/ delta x

=  x+ delta x- x / ( [x+ delta x/2-sqrt(X) ]2 +  [x+ delta x /2-sqrt(X) ] * [x/2-sqrt(X) ]] +  [x/2-sqrt(X) ]2

Post Merge: 2 years ago

no se subir imagenes sorry jajaja

Interesting that you used a difference of cubes to help solve the questions. Do you mind posting the written solution for clarity? You can upload an image by clicking the "reply" button below, and from there add an attachment.