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# A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. ...

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A month ago
 A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. ... 9. A 0.500 kg object is thrown vertically upward with an average applied force of 8.20 N by a student. The force is applied through a displacement of 1.50 m.a. What is the average net force acting on the object?b. What is the velocity of the object when it leaves the student’s hand? (Assume initial velocity is zero)This is the question and I have to use the grasp method. I'm not sure how to clearly find the answer if it is possible for a step-by-step solution, that would be great, have a good one! Read 154 times 4 Replies

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Educator
A month ago
 Let me know if you don't understand the process.Best of luck!
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A month ago Edited: A month ago, s.h_math
 Hi, why is a not the answer to a?Post Merge: A month agoI read it wrong,Post Merge: A month agoIs the direction for Fnet up or down? is the direction for acceleration up?thanks Post Merge: A month agoIn the answer sheet for b, it says the answer is 4.45 m/s
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Educator
A month ago
 Quote from: s.h_math (A month ago)In the answer sheet for b, it says the answer is 4.45 m/sYou're right I forgot to upload the rest of the answer:So, Fg is going down, it should be negative (-4.90). When we combine Fapp with -4.90, we get Fnet:Fnet = 8.20 + (-4.90) = 3.30 N. 3.30 N is positive.Does that make more sense?
wrote...
A month ago
 Yes it definitely did, thanks a lot!
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