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# Collision network

wrote...
Posts: 33
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1 months ago
 Collision network A 25 kg turkey is fired from a 1.1x10^3 kg turkey launcher. If the horizontal velocity of the turkey is 325 m/s east, what is the recoil of the launcher?Hi there, I'm kind of confused on how to solve for the recoil of the launcher, I have to show a step-by-step solution, but not sure how to solve this question. Read 100 times 3 Replies

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wrote...
Staff Member
1 months ago
 Another law of conservation of linear momentum problem:Thankfully, it is being fired horizontally, otherwise the problem would get annoying.Turkey: 25 kgLauncher: 1100 kgTurkey and launcher combined:  1125 kgInitial speed turkey and launcher: 0 m/sSpeed of turkey: 325 m/s1125 kg ( 0 m/s ) = 25 kg ( 325 m/s ) + 1100 kg ( v )0 = 8125 kg*m/s + 1100 kg ( v )Bring 8125 kg*m/s to the left:-8125 kg*m/s = 1100 kg ( v )Solve for v:-8125 kg*m/s / 1100 kg = vv = -7.4 m/s, which means 7.4 [west].
 - Master of Science in Biology- Bachelor of Science (Biology)- Bachelor of Education
wrote...
1 months ago
 Do you think you could possibly share the equation to what these numbers were plugged in 1125 kg ( 0 m/s ) = 25 kg ( 325 m/s ) + 1100 kg ( v )? Thanks!
wrote...
Staff Member
1 months ago Edited: 1 months ago, duddy
 Yes, of course. Remember I made reference to the law of conservation of linear momentum I used this law here initial: https://biology-forums.com/index.php?topic=1998690.msg5283630#msg5283630The main idea is that momentum = momentum, and depending on the situation, you may have to modify what you place on the left-side and what is placed on the right side. It's not a one-size fits all situation.How's that?
 - Master of Science in Biology- Bachelor of Science (Biology)- Bachelor of Education