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# 100 mL of 0.2 mol/L sodium carbonate solution and 200 mL of 0.1 mol/L calcium nitrate solution

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3 months ago
 100 mL of 0.2 mol/L sodium carbonate solution and 200 mL of 0.1 mol/L calcium nitrate solution 100 mL of 0.2 mol/L sodium carbonate solution and 200 mL of 0.1 mol/L calcium nitrate solution are mixed together. Calculate the mass of calcium carbonate that would precipitate and the concentration of the sodium nitrate solution that will be produced Read 50 times 1 Reply

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Educator
3 months ago
 First, write the balanced equation for the reaction.Determine the moles of reactant: number of moles = molarity x volume in LUsing stoichiometric relation between the reactants, determine the number of moles of the other reactant.Number of moles = Mass of compound / Molar mass of compoundUsing the stoichiometric relations established in the balanced equation, determine the limiting reagent.Using the stoichiometric relation between the limiting reagent and the desired product, determine the number of moles of the desired product.Mass of desired product = number of moles of product x molar mass of the productThe complete solution is shown below Attached file Thumbnail(s): You must login or register to gain access to this attachment.