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If in an △ABC, 2cosA·sinC=sinB, then the triangle is?

megan.xo

wrote...

Posts: 129

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2 years ago

If in an △ABC, 2cosA·sinC=sinB, then the triangle is?

If in an △ABC, 2cosA·sinC = sinB, then the triangle is?

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Bella_23

wrote...

#1

2 years ago

2cosA.sinC=sin(C+A)
=sinC.cosA+cosC.sinA
⇒cosAsinC−sinAcosC=0
⇒sin(C−A)=0
⇒C=A

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