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11 years ago
A 50.0-kg box is resting on a horizontal floor. A force of 250 N directed at an angle of 30.0° below the horizontal is applied to the box. The coefficient of static friction between the box and the surface is 0.400. What is the force of friction on the box?
A) 31.9 N
B) 196 N
C) 217 N
D) 246 N
E) 616 N
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wrote...
Valued Member
11 years ago
C
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wrote...
11 years ago
Ff = m(?)

Fr = m(9.81)

Fr = 490.5 N

Fy = 250sin30°

Fy = 125 N

F = 125 + 490.5 N = 615.5 N

Ff = 615.5(0.400)

D.
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