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Arrange the given monomers in decreasing order of reactivity towards anionic polymerization.

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Arrange the given monomers in decreasing order of reactivity towards anionic polymerization.

Question 1.

Arrange the given monomers in decreasing order of reactivity towards cationic polymerization.

An illustration depicts three monomers.The first monomer labeled Roman numeral 1 has a SMILES string of C=CC=O.The second monomer labeled Roman numeral 2 has a SMILES string of C=CN.The third monomer labeled Roman numeral 3 has a SMILES string of CC(=O)OC=C.

An illustration depicts three monomers.The first monomer labeled Roman numeral 1 has a SMILES string of C=CC=O.The second monomer labeled Roman numeral 2 has a SMILES string of C=CN.The third monomer labeled Roman numeral 3 has a SMILES string of CC(=O)OC=C.

▸ II > I > III

▸ III > I > II

▸ III > II > I

▸ I > III > II

▸ II > III > I

Question 2.

Arrange the given monomers in decreasing order of reactivity towards anionic polymerization.

An illustration depicts three monomers.The first compound labeled as Roman numeral one has a carbon atom double bonded to a methylene compound and single bonded to a methoxy group, O C H 3. The second compound labeled as Roman numeral two has a carbon atom double bonded to a methylene compound and single bonded to a trifluoromethyl group, C F 3. The third compound labeled as Roman numeral three has a SMILES string of CC=C.

▸ III > II > I

▸ II > III > I

▸ I > III > II

▸ III > I > II

▸ II > I > III

Textbook

Organic Chemistry

Edition: 4^th

Author: Klein

Read 74 times

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Thanks for your help!!

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