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tsk tsk
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2 years ago

Question 1.

Arrange the given monomers in decreasing order of reactivity towards cationic polymerization.

An illustration depicts three monomers.The first monomer labeled Roman numeral 1 has a SMILES string of C=CC=O.The second monomer labeled Roman numeral 2 has a SMILES string of C=CN.The third monomer labeled Roman numeral 3 has a SMILES string of CC(=O)OC=C.


▸ II > I > III

▸ III > I > II

▸ III > II > I

▸ I > III > II

▸ II > III > I

Question 2.

Arrange the given monomers in decreasing order of reactivity towards anionic polymerization.

An illustration depicts three monomers.The first compound labeled as Roman numeral one has a carbon atom double bonded to a methylene compound and single bonded to a methoxy group, O C H 3. The second compound labeled as Roman numeral two has a carbon atom double bonded to a methylene compound and single bonded to a trifluoromethyl group, C F 3. The third compound labeled as Roman numeral three has a SMILES string of CC=C.


▸ III > II > I

▸ II > III > I

▸ I > III > II

▸ III > I > II

▸ II > I > III
Textbook 
Organic Chemistry

Organic Chemistry


Edition: 4th
Author:
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itashiaitashia
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tsk Author
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2 years ago
I appreciate what you did here, answered it right Smiling Face with Open Mouth
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Thanks
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Helped a lot
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