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Anonymous samantacastillo
wrote...
2 months ago
1) se the following information to answer the next two questions.

Three different genes determine the coat colour of cats. One of the genes controls the black-based coat colour. There are three alleles for black-based coat colour genes with the following order of dominance: black (B) > chocolate (bch) > cinnamon (bc).

Two black cats were crossed. The offspring produced were three black kittens and one chocolate kitten.

A) Which of the following rows identifies the possible genotypes of the parents?

a. Parent 1         Parent 2
      BB                   Bb^ch

b. Parent 1          Parent 2
       Bb^c                  Bb^c

c. Parent 1           Parent 2
       Bb^c                    BB

d. Parent 1          Parent 2
        Bb^ch                Bb^c


B) What is the probability of having a male chocolate kitten?

a. 0.25

b. 0.06

c. 0.13

d. 0.50








2) Use the following information to answer the next three questions.

In rabbits, white fur colour (W) is dominant over black fur colour (w), and upright ears (U) are dominant over floppy ears (u).

A white rabbit with upright ears, heterozygous for both traits, mated with a homozygous white rabbit with floppy ears.

A) What are the possible phenotypes of the offspring?

a. White floppy and black upright

b. Black floppy and black upright

c. Black floppy and white upright

d. White floppy and white upright



B) A heterozygous white rabbit with floppy ears mated with a black rabbit with heterozygous upright ears.

What is the probability of having a black kit with upright or floppy ears?

a. 0.50

b. 0.25

c. 0.06

d. 0.13



C) Two white rabbits with upright ears, heterozygous for both traits, mated and produced offspring.

What is the probability the first offspring has black fur with upright ears and the second offspring has white fur with floppy ears?

a. 9 / 256

b. 3 / 8

c. 3 / 16

d.  3 / 128

e. 1 / 16









3) In Labrador retrievers, two genes work together to determine coat colour.The first gene affects the colour of the dark pigment, eumelanin. A genotype containing at least one dominant allele of this pigment gene results in black pigmentation (B_). A homozygous recessive genotype of this gene results in brown pigmentation.

The second gene affects whether the pigment eumelanin is present in the fur. If a dog has one dominant allele for this expression gene (E_), fur colouration is determined by the pigment gene. If a dog is homozygous recessive for the extension trait, the dog will have a yellow coat.

              Description                                                                                Genotype(s)
             
               Black coat                                                                   BBEE / BbEE / BBEe / BbEe

           Chocolate coat                                                                          bbEE / bbEe

             Yellow coat                                                                            BBee / Bbee / bbee

What percentage of chocolate labs would be produced from the mating of a yellow lab who is homozygous recessive for both genes to a black lab who is heterozygous for both coat colour and expression?

a. 25%

b. 50%

c. 33%

d. 75%









4) A male and female have three children, all girls. The couple is expecting their fourth child. The probability their fourth child will be female is __i__, and the probability the couple will have four female children is __ii_.

The row that indicates the correct probabilities is

a.       i                     ii
       1 /4               1 / 8

b.      i                      ii
     1 / 16               1 /4

c.      i                        ii
      3 / 4                1 / 4

d.      i                        ii
       1 /2                  1 / 16










5) For each of the following traits, select whether it is a continuous trait or a discrete trait in humans.

Trait                     Discrete trait / Continuous trait
Height                                    Answer
 

Albinism                                Answer
 

Learning ability                     Answer
 

Body weight                          Answer
 

Number of fingers                Answer
 

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Answer verified by a subject expert
Anonymousbio_man
wrote...
1 months ago
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Quote
1) se the following information to answer the next two questions.

Three different genes determine the coat colour of cats. One of the genes controls the black-based coat colour. There are three alleles for black-based coat colour genes with the following order of dominance: black (B) > chocolate (bch) > cinnamon (bc).

Two black cats were crossed. The offspring produced were three black kittens and one chocolate kitten.

A) Which of the following rows identifies the possible genotypes of the parents?

a. Parent 1         Parent 2
      BB                   Bb^ch

b. Parent 1          Parent 2
       Bb^c                  Bb^c

c. Parent 1           Parent 2
       Bb^c                    BB

d. Parent 1          Parent 2
        Bb^ch                Bb^c


B) What is the probability of having a male chocolate kitten?

a. 0.25

b. 0.06

c. 0.13

d. 0.50

Parent 1 : Bbch
Parent 2 : Bbc


What is the probability of having a male chocolate kitten?

0.13

Quote
C) Two white rabbits with upright ears, heterozygous for both traits, mated and produced offspring.

What is the probability the first offspring has black fur with upright ears and the second offspring has white fur with floppy ears?

a. 9 / 256

b. 3 / 8

c. 3 / 16

d.  3 / 128

e. 1 / 16

Answered here: https://biology-forums.com/index.php?topic=1815098.0

Quote
3) In Labrador retrievers, two genes work together to determine coat colour.The first gene affects the colour of the dark pigment, eumelanin. A genotype containing at least one dominant allele of this pigment gene results in black pigmentation (B_). A homozygous recessive genotype of this gene results in brown pigmentation.

The second gene affects whether the pigment eumelanin is present in the fur. If a dog has one dominant allele for this expression gene (E_), fur colouration is determined by the pigment gene. If a dog is homozygous recessive for the extension trait, the dog will have a yellow coat.

              Description                                                                                Genotype(s)
             
               Black coat                                                                   BBEE / BbEE / BBEe / BbEe

           Chocolate coat                                                                          bbEE / bbEe

             Yellow coat                                                                            BBee / Bbee / bbee

What percentage of chocolate labs would be produced from the mating of a yellow lab who is homozygous recessive for both genes to a black lab who is heterozygous for both coat colour and expression?

a. 25%

b. 50%

c. 33%

d. 75%

25%

A yellow lab who is homozygous recessive for both genes will have the genotype 'bbee' and a black lab who is heterozygous for both genes will have the genotype 'BbEe'. A cross between these two will give the following results:



As can be seen from the punnet square, 25% offsprings will have chocolate (brown) coat due to being homozygous recessive for coat color and heterozygous for expression. 25% will be black and 50% will have yellow coats due to being homozygous recessive for expression.

Quote

4) A male and female have three children, all girls. The couple is expecting their fourth child. The probability their fourth child will be female is __i__, and the probability the couple will have four female children is __ii_.

The row that indicates the correct probabilities is

a.       i                     ii
       1 /4               1 / 8

b.      i                      ii
     1 / 16               1 /4

c.      i                        ii
      3 / 4                1 / 4

d.      i                        ii
       1 /2                  1 / 16

(D) The probability that two independent events will occur together will be determined by the product of their probabilities, according to the probability multiplication rule.
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Anonymous Author
wrote...
1 months ago
thanks
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