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chrysie1981 chrysie1981
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8 months ago
A researcher wishes to estimate the proportion of adults who have high speed internet access what size sample should be obtained if she wishes the estimate to be within 0.05 with 95% confirmed

a) she uses a previous estimate of 0.36​?
​(b) she does not use any prior​ estimates?
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bolbolbolbol
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7 months ago
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Now, with a PRELIMINARY ESTIMATE of .36, p̂ = .36, and q̂ = 1 - p̂ = 1 - .36 = .64
Since this is a 99% CONFIDENCE INTERVAL, then significance level is

0.01/2 or 0,005 so zcritical = 2.575

E (Margin of Error) = .05

Therefore, n = p̂q̂ (zc/e)^2

n = 0.03 x 0.64 x (2.575/0.05)^2 = 0.2304x(51.5)^2 = 0.2304 (2,652.25) = 611.0784 , rounded to 612 adults
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chrysie1981 Author
wrote...

8 months ago
this is exactly what I needed
wrote...

Yesterday
Smart ... Thanks!
wrote...

2 hours ago
Thanks
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