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Anonymous samantacastillo
wrote...
A year ago
1) In tomatoes, red fruit (R) is dominant over yellow fruit (r). In a tomato plant population exhibiting Hardy–Weinberg equilibrium, if allele r has a frequency of 0.72, what percentage of the population is homozygous dominant for this trait?



Express your answer using three significant digits.

Answer %











2) In mice, black fur (W) is dominant over white fur (w). In an ideal mouse population exhibiting Hardy–Weinberg equilibrium, 189 mice out of 215 have white fur.



Calculate the number of mice that are heterozygous dominant for the fur colour gene in the population.



Express your answer rounded to the nearest whole number.

Answer










3) In horses, tobiano is a white spotting pattern. The tobiano allele (T) is dominant over the non-tobiano (t) allele. In an ideal horse population exhibiting Hardy–Weinberg equilibrium, 375 horses out of 400 are non-tobiano.



a. Calculate the number of homozygous dominant tobiano horses.   Answer

b. Calculate the number of heterozygous horses.                               Answer

c. Calculate the number of tobiano horses in the population.            Answer



Express your answer rounded to the nearest whole number.
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AnonymousAnonymous
wrote...
A year ago
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Anonymous Author
wrote...
A year ago
sorry question 3 is not been answered can you please help
Anonymous
wrote...
A year ago
Answer :

Hardy-Weinberg Equilibrium :

Frequency of non-tobiano (q​​​​​​2)= 375/400 = 0.94

q = √q2 = √0.94 = 0.97

p = (1-q) = (1-0.97) = 0.03

Homozygous dominant = p​​​​​​2 = (0.03)(0.03) = 0.0009

Heterozygous = 2pq = 2(0.97)(0.03) = 0.0582

Homozygous recessive = q​​​​​​2 = (0.97)(0.97) =0.94

(a). The number of the homozygous dominant tobiano horses (TT) = (0.0009)(400) = 0.36

(b). The number of the heterozygous horses (Tt) = (0.0582)(400) = 23.28

(c). The number of tobiano horses (TT + Tt) = (400 - 375) = 25
Anonymous Author
wrote...
A year ago
Thank you so much
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