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# Compartment model

wrote...
Posts: 10
Rep:
2 months ago
 Compartment model Literature reports suggest that azatamycin follows a two compartment model in human subjects. After administering a single IV dose (10 mg/kg) in eighteen normal volunteers, the investigators demonstrated that the equation best describing azatamycin kinetics was as followsCp = 19 e - 4.8 t + 13 e - 0.15 t k21 = 2.04 hr-1What is the hybrid distribution half-life? Read 40 times 5 Replies

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Anonymous
wrote...
2 months ago
 Hello,$$C_p=19e-4.8t+13e-0.15t$$$$k_{21}=2.04\ hr^{-1}$$Is this what the equations look like?
Gmill Author
wrote...
2 months ago
 yes
Anonymous
wrote...
2 months ago
 I don't think so. Are you sure it is not:$$C_p=19e^{-4.8t}+13e^{-0.15t}$$??
Anonymous
wrote...
2 months ago
 The hybrid distribution half-life is a parameter that describes the distribution of a drug between the central and peripheral compartments in a two-compartment model. It is calculated as the ln(2) divided by the sum of the elimination rate constant (k10) and the distribution rate constant (k12).In this case, the elimination rate constant (k10) is not given, but we can use the given information to calculate k10. From the equation Cp = 19 e^(-4.8t) + 13 e^(-0.15t), we can see that the initial concentration (at t=0) is Cp(0) = 19 + 13 = 32 mg/L. At steady state, the infusion rate (R) equals the elimination rate (k10Cp), so we can set R = k10Cpss, where Cpss is the steady-state concentration. Solving for k10, we get:k10 = R/Cpss = (10 mg/kg * 70 kg)/(32 mg/L * 1) = 21.875 hr^-1Now we can calculate the hybrid distribution half-life:k12 = 2.04 hr^-1k10 = 21.875 hr^-1hybrid distribution half-life = ln(2) / (k10 + k12)= ln(2) / (21.875 + 2.04) hr^-1= 0.030 hr or 1.8 minutesTherefore, the hybrid distribution half-life of azatamycin in human subjects after a single IV dose (10 mg/kg) is approximately 1.8 minutes.
Gmill Author
wrote...
2 months ago Edited: 2 months ago, Gmill
 yes it's thisPost Merge: 2 months agoThank you!
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