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Home Q & A Board Science-Related Homework Help Mathematics Statistics and Probability
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msidhu msidhu
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A year ago
In a chi-square goodness-of-fit test, the value of the test statistic is found to be 11.89 and there are 5 degrees of freedom. Usingα= 0.05, the null hypothesis would be:


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not rejected because thep-value for this test is less than 0.05.



▸

rejected because thep-value for this test is less than 0.05.



▸

not rejected because thep-value for this test is greater than 0.05.



▸

rejected because thep-value for this test is greater than 0.05.

Textbook 
Introductory Statistics: A Problem-Solving Approach

Introductory Statistics: A Problem-Solving Approach


Edition: 3rd
Author:
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chinwe20chinwe20
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A year ago
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msidhu Author
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A year ago
Smart ... Thanks!
shangshang
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Yesterday
Correct Slight Smile TY
Morgan-C
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2 hours ago
You make an excellent tutor!
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