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misserz0210 misserz0210
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9 months ago

If protons are accelerated from rest in a Van de Graff accelerator through a potential difference of 1.00 MV, what is their resulting speed?



3.67 × 108 m/s



6.25 × 107 m/s



9.79 × 106 m/s



1.38 × 107 m/s



6.92 × 106 m/s

Textbook 
College Physics

College Physics


Edition: 5th
Author:
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careytrancareytran
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9 months ago
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