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OldSpice OldSpice
wrote...
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Posts: 6434
Rep: 33 0
8 years ago
If 1.020 g of KHC8H4O4 (204.23 g/mol) is completely neutralized with 0.200 M KOH, what volume of potassium hydroxide is required?
   KHC8H4O4(aq) + KOH(aq) ? K2C8H4O4(aq) + 2 H2O(l)
A) 12.5 mL
B) 20.0 mL
C) 25.0 mL
D) 40.0 mL
E) 50.0 mL
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ElectricElectric
wrote...
#1
Top Poster
Posts: 6428
Rep: 688 0
8 years ago
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.silent.boss
OldSpice Author
wrote...
#2
8 years ago
Perfect!

..Thank you so much for your support
wrote...
#3
8 years ago
My pleasure
.silent.boss
Anonymous
wrote...
#4
A week ago
Help! The answer is missing an explanation...
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