Hi!
(Number of recaptures in second catch / Total number in second catch) = (Number marked in first catch / Total population N)
If 10/50 = 50/N, then N = 250 chipmunks.
i. You later discover that you sampled the one area of the park that was most favored by the chipmunks.If the area was favored by the chipmunks, you most likely captured more chipmunks in this area than you would have caught in other areas of the park. As a result, your estimate of the population size would be larger than if you had sampled more of the park.
ii. You later discover that the chipmunks were licking the mark off of each others’ backs.Some of the recaptured chipmunks that were counted as unmarked could have been among those that had their marks licked off. As a result, your estimate of population size would be higher than if the marks had not been licked off. For example, if 10 of those captured had licked off their marks, the actual recapture ratio would be 20/50. Then the population estimate would change to 125 (rather than 250) chipmunks in the population.
c. What modifications could you make to your sampling program to help insure more accurate estimates of population size?At a minimum, you should sample several areas of the park and use a marking system that cannot be removed easily.
I hope this helped you out NAZ,
Bye bye
Quick Reply
