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Whelan Whelan
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8 years ago
How many grams of CaCl2 are formed when 25.00 mL of 0.00237 M Ca(OH)2 reacts with excess Cl2 gas?

2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCl)2(aq) + CaCl2(s) + 2 H2O(l)

A) 0.00329 g
B) 0.00658 g
C) 0.0132 g
D) 0.0304 g
Textbook 
Introductory Chemistry Essentials

Introductory Chemistry Essentials


Edition: 5th
Author:
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hbutler2hbutler2
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