Phenylketonuria (PKU) is a condition of newborns caused by an autosomal recessive allele. The incide

There are 0.000384 people in Turkey that have this problem. So, of the 2600 people, 0.0384% have the condition and are, let's say rr is their genotype.

The question is asked for carriers though, so people who are Rr, one dominant gene and one defected.

So, you have to use the hardy-Weinberg equation.

p^2 + 2pq + q^2 = 1

q^2 = 0.000384

q = SQRT(0.000384)

q = 0.01959

Use: p + q = 1

p = 1 - 0.01959 = 0.9804

Now, use the equation again:

2(p)(q) = 2(0.9804)(0.01959) = 0.03841

Then you multiple that by 100 to get 3.8%

Hopefully (a) is the answer.