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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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OldSpice OldSpice
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9 years ago
The formula for the illegal drug cocaine is C17H21NO4 (303.39 g/mol). What is the percentage of carbon in the compound?
A) 3.959%
B) 4.618%
C) 6.991%
D) 21.09%
E) 67.30%
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ElectricElectric
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#1
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9 years ago
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.silent.boss

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OldSpice Author
wrote...
#2
9 years ago
Perfect!

..Thank you so much for your support
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#3
9 years ago
My pleasure
.silent.boss
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#4
A year ago
The formula for the illegal drug cocaine is C17H21NO4. What is the mass percentage of oxygen in the compound?
wrote...
#5
Educator
A year ago
Quote from: loeinjhonson (A year ago)
The formula for the illegal drug cocaine is C17H21NO4. What is the mass percentage of oxygen in the compound?
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