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Home Q & A Board Science-Related Homework Help Mathematics
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quixie quixie
wrote...
solved
8 years ago
Find the derivative of the function.

f(w) = \({w^{2}}{sec^{2}}(9w)\)

a. f'(w) = \(18w{sec^{2}}(9w)tan(9w)\)

b. f'(w) = \(2w{sec^{2}}(9w)+18{w^{2}}{sec^{2}}(9w)tan(9w)\)

c. f'(w) = \(2w{sec^{2}}(9w)+18{w^{2}}sec(9w)\)

d. f'(w) = \(2w{sec^{2}}(9w)+18{w^{2}}{sec^{2}}(9w){tan^{2}}(9w)\)
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#1
Educator
8 years ago
(A)
quixie Author
wrote...
#2
8 years ago
Thank you for your help!
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