High school physics homework problem?

By definition, if forces are balanced constant velocity occurs.  So when 8.6 N applied force produces constant velocity, you know the force of friction is -8.6 N.

an object that weighs 32 N has a mass of 3.3 kg

a = Fnet / m   =  Fapplied - Ffriction / mass   When you remove the applied force it becomes zero.      

a = 0 - 8.6 N / 3.3 kg  So                           a = -2.6 m/s/s

The normal force n equals the weight of the box.
n = 32N
The friction force equals the normal force times the coefficient of friction ?
f = 32N(?)
For the box to be in motion with constant velocity, the applied force F must equal the friction force. Therefore the friction force f is:
f = 8.6N
When the applied force is removed the friction force causes the box to decelerate. We can find out the magnitude of the deceleration by writing an  f = ma equation, or, a = f/m
The mass of the box is 32N/9.8m/s^2 = 3.2653kg
Therefore, a = f/m
a = 8.6N/3.2653kg = 2.634m/s^2
Deceleration magnitude = 2.634m/sa^2